Question

16. If a body having initial velocity zero is movi with uniform acceleration 25meter per second square the distance travelled by it in fifth second will be (a) 36 metres (b) 40 metres (C) 100 metres (d) Zero​

Answer 1

Answer:

36 m

Explanation:

Given Data :-

Initial velocity = 0

Acceleration = 8 m/s^2          [your data is wrong]

Formula to find distance travelled on nth second :-

s = u + a/2 (2n - 1)

s = 0 + 8/2 (2(5) - 1)

s = 36 m

Answer 2

Answer:

If a body having initial velocity zero is moving with a uniform acceleration of 25ms⁻², then the distance travelled by it in the fifth second will be 112.5m

Explanation:

Given that,

      initial velocity, u = 0

        acceleration, a = 25ms⁻²

          nth second, n = 5

we know that the distance travelled by $n^{th}$ second is

            $S_n = u + \frac{a}{2} (2n-1)$

then,  the distance travelled by it in the fifth second is

           S₅ = 0 + 0.5 × 25 × (2×5-1)

⇒             = 112.5 m

Thus, the distance travelled by the body in the fifth second is 112.5 m

Note: none of the options is correct if acceleration is 25 ms⁻²