16. If A speaks the truth 80% of the times, B speaks the truth 60% of the times. What is the probability that they tell the truth at the same time
absh90:
probability that A speaks truth is 80/100=0.8 probability that B speaks truth is 60/100=0.6 since both A and B are independent of each other so PROBABILITY OF A INTERSECTION B = P(A) *P(B) =0.8 * 0.6 = 0.48
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[80/100]×[60/100]
=4800/10000
=48/100
=48%
options are 0.14 , 0.48
0.48 is correct
yes. but, how can you explain?
will you mark me as brainliestbif i explain
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48% is the probability
probability that A speaks truth is 80/100=0.8 probability that B speaks truth is 60/100=0.6 since both A and B are independent of each other so PROBABILITY OF A INTERSECTION B = P(A) *P(B) =0.8 * 0.6 = 0.48
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