Question

16. If a total of 6.67 x 10^-18J
energy is received from the
radiation of 6000Angstrom,
then the number of photons
received is *

Answer 1

Answer:

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Answer 2

Answer:

Given wavelength =3000A∘

E=hν

c=hν

v=λc​

E=h.λc​

=6.626 x 10−34 × 3000 × 10−93 × 108​

=6.626 x  10−9108​

=6.626 x 10−34 X 108 X 107

=6.626 x 10−34   X 1015

E= 6.626 x 10−34   X 1019Joules.

Explanation:

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