Question

16.if a*x=b*y=c*z and b/a=c/b, then 2z/x+z is

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Answer 1

Answer:

What we have is:

a^x=b^y=c^z

2. b²=ac

Now taking xz-th power on both sides of 2, we have:

(b²)^(xz)=a^(xz). c^(xz)

or, b^2xz= {(a^x)^z}.{(c^z)^x}

or, b^2zx= {(b^y)^z}.{(b^y)^x} {using 1}

or, b^2zx=(b^yz).(b^yx)=b^(yz+yx)

Therefore, 2zx=yz+yx

or, y=2zx/(z+x)