16. If points A(5, p), B(1,5), C( 2, 1) and D(6, 2) form a square ABCD, then p=
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Vertices of a square are A(5, p), B(1, 5), C(2, 1) and D(6, 2).
The diagonals bisect each other at O
O is the mid-point of AC and BD
O is mid-point of BD, then
CO-ordinates of O will be \(\left(\frac{1+6}{2}, \frac{5+2}{2}\right)\)
or \(\left(\frac{7}{2}, \frac{7}{2}\right)\)
\(\because \) O is mid-point of AC also
\(\therefore \frac{p+1}{2}=\frac{7}{2} \Rightarrow p+1=7\)
\(\Rightarrow\) p = 7 - 1 = 6
Therefore the choice is: C
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