Question

16. If Sec A =13/12, Than Tan A = ...... *​

Answer 1

Answer:

tanθ = 5/12

Step-by-step explanation:

Given : sec A = 13/12

We know that , tan²θ = sec²θ - 1

tan²θ = (13/12)² - (1)²

by using a²- b² = (a+b)(a-b)

tan²θ = ((13/12)+1)((13/12)-1)

tan²θ = ((13+12)/12)((13-12)/12)

tan²θ = (25/12)(1/12)

tan²θ = 25/144

by transferring square to RHS side

tanθ = √(25/144)

tanθ = 5/12