Question

16. If the perimeter of a circle is
equal to that of a square, then
the ratio of their areas is: *
O 22:7
O 7:22
O11:14
014:11​

Answer 1

Answer:

Solution : Let radiust of circle be r and side of a square be a. <br> According to the given condition, <br> Perimeter of a circle = Perimeter of a square <br> `:. 2pir = 4a rArr a = (pir)/(2)` …..(i) <br> Now, `("Area of circle")/("Area of square") =(pir^(2))/((a)^(2))=(pir^(2))/(((pir)/(2))^(2))`[from eq. (i)] <br> `=(pir^(2))/(pi^(2)r^(2)//4)=(4)/(pi)= (4)/(22//7)=(28)/(22)=(14)/(11)`