Question

16. If x = 7 +4v3 and xy = 1, then x2 +
=
a) 64 b) 134 c) 194 d) 1/49​

Answer 1

Answer:

Given, x = 7 + 4√3 , xy = 1 Y = 1x1x = 1717+ 4√3 = 7 - 4√3 Y2 = 1x21x2 = 49 + 48 - 56√3 = 97 - 56√3 Similarly, x = 1y1y = x2 = 1y21y2 = ( 7 + 4√3)2 = 49 + 48 + 56√3 = 97+ 56√3 So, 1x21x2 + 1y21y2 = 97 + 56√3 + 97 – 56√3 = 194Read more on Sarthaks.com - https://www.sarthaks.com/1069455/if-x-7-43-and-xy-1-then-1-x-2-1-y-2-a-64-b-134-c-194-d-1-49