Question

16 In a
parallelogram PQRS, LQ=C40-5)
and 25= (3x + 10). Calculate LQ and LR.​

Answer 1

Answer:

We know that, opposite angles of a parallelogram are equal.

∴ ∠Q=∠S

⇒ 4x−5=3x+10

⇒ 4x−3x=10+5

⇒ x=15

⇒ ∠Q=(4x−5)

o

=(4×15−5)

o

=55

o

We know that, sum of adjacent angles of parallelogram is 180

o

⇒ ∠Q+∠R=180

o

⇒ 55

o

+∠R=180

o

∴ ∠R=125

o