Question

16. In fig DE || OQ and DF || OR. Show that EF ||
QR
Soln :
A POQ, DE||OQ
.. By Thales theorem
PE PD
EQ OD
In A PRO, DF || OR
. By Thales theorem
.........(1)​

Answer 1

Answer:

In △ABC AB=AC

⇒∠B=∠C (Angles opposite to equal sides are equal)

Now using angle sum property

∠A+∠B+∠C=180

∘

⇒80

∘

+∠C+∠C=180

∘

⇒2∠C=180

∘

−80

∘

⇒∠C=

2

100

∘

=50

∘

now ∠C+∠x=180

∘

(Angles made on straight line (AC) are supplementary)

⇒50

∘

+∠x=180

∘

⇒∠x=180

∘

−50

∘

=130

∘