Math, asked by shibanishil862, 4 days ago

16. In the alongside diagram, the bisectors of interior angles of the parallelogram PQRS enclose a quadrilater al ABCD. S R А D B C P Q Show that: (1) ∆PSB + ∆SPB = 90° (ii) ∆PBS = 90° (iii) ∆ABC = 90° (iv) ∆ADC = 90° (v) ∆A = 90° (vi) ABCD is a rectangle.

pls answer this. it is very important.​

Answers

Answered by XxOollMrVENOMIloOxX
3

16. In the alongside diagram, the bisectors of interior angles of the parallelogram PQRS enclose a quadrilater al ABCD. S R А D B C P Q Show that: (1) ∆PSB + ∆SPB = 90° (ii) ∆PBS = 90° (iii) ∆ABC = 90° (iv) ∆ADC = 90° (v) ∆A = 90° (vi) ABCD is a rectangle.

pls answer this. it is very important.

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Answered by ayushimw12
0

Answer:

(vi) ABCD is a rectangle

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