Question

16. In the fig. AC I BD and C is the midpoint of BD.
a) State the three pairs of equal parts in triangles ACB and ACD
b) Is ZACB = ZACD? Give reason
c) Is ZBAC = ZDAC? Give reason
B В
answer

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

(a) bc=cd (c is the midpoint of bd; intersecting bd in two equal halves)

ac=ac (common line in ∆abc & ∆acd)

∠acb=∠acd (linear pair)

(b)∠acb=acd because it's a linear pair/ supplementary angles.

(c) from answer (a) we can say bc=cd

ac=cd

& ∠acb=∠acd

Hence, according to ASA congruence (angle side angle) ∆abc=∆acd

therefore, CPCTC (corresponding parts of congruent triangle is congruent) that is:

∠bac=∠dac.

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