Question

16. In the figure, AABC - APQR. Also area (AABC) = 4. area (APQR). IF BC = 12 cm, find EF ​

Answer 1

Answer:

ΔABC∼ΔPQR

ar(ΔABC)=4ar(ΔPQR)

area ΔPQR

area ΔABC

=

1

4

area(ΔPQR)

area(ΔABC)

=

QR

2

BC

2

1

4

=

QR

2

BC

2

⇒(

1

2

)

2

=(

QR

12

)

2

1

2

=

QR

12

⇒QR=

2

12×1

=6

QR=6cm