16. In the figure, AE bisects ZBAD and Af
bisects ZCAD and AE prependicular AF Show that
B, A, C are collinear,
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AE bisects ∠BAD
AF bisects ∠CAD
AE⊥ AF
∠CAF = ∠FAD (this is given)
∠BAE = ∠EAD (this is also given)
∠EAD + ∠FAD = 90° = ∠EAF (this is given too)
∠EAD + 1/2∠BAD and ∠FAD = 1/2 ∠CAD
1/2 ∠CAD + 1/2 ∠BAD= 90°
∠CAD + ∠BAD = 2x 90°
= 180°
The colinear point will lie on the straight line
and the straight line will make an angle of 180° on both sides.
∠CAD + ∠BAD
= ∠CAB = 180°
C,A, and B are colinear.
hope it helps
tq./
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