Question

16. In the given branch PQ of a circuit, electric current
i = (5t + 2) A is flowing, where t is time in second.
At t = 1, the potential difference between points
Pand Q is
10 V
W 00000
52H​

Answer 1

Given:

i = (5t + 2) A

t =1

To find:

potential difference = V =?

Explanation:

The potential difference is the electric potential between two points.

This potential difference is given by

$\displaystyle V = L \frac{dI}{dt}$

where L is inductance in Henry & it constant.

∴$\displaystyle V =L \frac{d}{dt}(5t +2)$

  V = 5L V

So V is proportional to time.

∴ At t  = 1, V = 5L V