Physics, asked by Nidhi2903, 1 year ago

16. In the given circuit if point C is connected to the
earth and potential of +2000 V is given to the point
A, the potential at B is

(1) 1500 V
(2) 1000 V
(3) 400 V
(4) 1600 V

Attachments:

Answers

Answered by blahblahblah63
18

Answer:

3) 400 V

Explanation:

net equivalent capacitance= {16*16/16+16} +8 = 16 =C2

{V(A) - V(B)} C1= {V(B) - V(C)} C2

{2000-V(B) }* 4 = {V(B) - 0} *16

V(B) = 400V

Answered by anirudhayadav393
1

Concept Introduction: Capacitors stores energy and charge.

Given:

We have been Given: Two resistors connected in series are

16uf

and one connected in series is

8uf

Potential is given as

2000v

To Find:

We have to Find: the potential at B is

  1. 1500 V
  2. 1000 V
  3. 400 V
  4. 1600 V

Solution:

According to the problem, Equivalent Capacitance is

 c_{p} =  \frac{16 \times 16}{16 + 16} + 8 =  \frac{256}{32}   + 8 =  \frac{256 + 256}{32}  =  \frac{512}{32}  = 16uf

therefore the potential at point B is

( v_{a} -  v_{b}) \times  c_{1} = ( v_{b} -  v_{c}) \times  c_{p}

therefore putting the values,

(2000 -  v_{b} ) \times 4 = ( v_{b} - 0) \times 16 \\ 2000 -  v_{b} = 4 v_{b} \\ 5 v_{b} = 2000 \\  v_{b} = 400v

Final Answer: The potential at Point B is

400 \: v

#SPJ2

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