Question

16. In the quadrilateral ACED, angle CAD = 100°
= angle D and angle E = 50°. Show that (i) DE < DB
(ii) AB < BC.
​PLEASE tell the answer

Answer 1

Step-by-step explanation:

For this we have to find FOUR of the angles

For this we have to find FOUR of the anglesthey are angle ACE , angle ABC ,angle CAB and angle ACB...

NOW FOLLOWING IS THE SOLUTION TO FIND THEM

I. ANGLE -ACE=360°-250°=110°

ANGLE -ACE=360°-250°=110°2. ANGLE-ABC=180°-150°=30°

ANGLE -ACE=360°-250°=110°2. ANGLE-ABC=180°-150°=30°3. ANGLE-CAB=180°-100°=80°

ANGLE -ACE=360°-250°=110°2. ANGLE-ABC=180°-150°=30°3. ANGLE-CAB=180°-100°=80°4. ANGLE-ACB=180°-110°=70°

NOW TO PROVE LINE SEGMENT DE IS SHOTER THAN DB

PROOF- (angle ABC) is 30° and (angle DEA is 50°)

PROOF- (angle ABC) is 30° and (angle DEA is 50°)means angle DEA IS GREATER THAN ANGLE ABC

so the conclusion is the line opposite to the larger angle is always larger....and the line opposite to the smaller angle is smaller

so the conclusion is the line opposite to the larger angle is always larger....and the line opposite to the smaller angle is smallermeans the line opposite to angle ABC is smaller

so the conclusion is the line opposite to the larger angle is always larger....and the line opposite to the smaller angle is smallermeans the line opposite to angle ABC is smaller and the.line opposite to the angle DEA is.larger..

HENCE PROVED-DE < DB

2. TO PROVE - AB < BC.

TO PROVE - AB < BC.PROOF- we observed above that angle CAB is gerater than angle ACB by 10° difference.

TO PROVE - AB < BC.PROOF- we observed above that angle CAB is gerater than angle ACB by 10° difference.hence according to the theory says that the line opposite to larger angle is larger means the line opposite to angle CAB (BC) is greater than the line opposite to angle ACB ( AB ) is smaller.

HENCE PROVED-.