Math, asked by khushi13251, 8 months ago

16 In triangle ABC , BC is produced to D . angle A =x + 30°, angle B =3x+25° and angle ACD = 5x - 5°. Find x and angle B​

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Answered by tabassumn12
2

Answer:

Step-by-step explanation:

Angle a = x+30

Angle b = 3x+25

Angle ACD = 5x-5

According to exterior angle property:

ACD = a=b

5x-5 = x+30 + 3x + 25

5x-5 = 4x + 55

5x-4x = 55+5

x= 60

Angle b = 3*60 +25

Angle b = 180 + 25

Angle b = 205

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