Question

16. In two separate collisions, the coefficients of restitutions 'e,' and 'e, are in the ratio 3 : 1. In the first
collision, the relative velocity of approach is twice the relative velocity of seperation. Then the ratio
between the relative velocity of approach and relative velocity of seperation in the second collision is
1) 1:6
2) 2:3
3) 3:2
4) 6:1​

Answer 1

Answer:

We know that: e=

relative velocity before collision

relative velocity after collision

Given :

e

2

e

1

=

1

3

,e

1

=

2

1

⇒

e

2

(

2

1

)

=

1

3

⇒e

2

=

6

1

So, the ration between relative velocity of approach and the relative velocity of separation in the second collision is 6:1.