Question

16. int x = 10, y = 12, z;
z = (x++ * y++) +- y/2;​

Answer 1

Answer:

++x is called preincrement while x++ is called postincrement. after the code is run both a and b will be 1 but x will be 2. These are known as postfix and prefix operators. Both will add 1 to the variable but there is adifference in the result of the statement.

Explanation:

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