Question

16. It tan 2A - Cot (A -18) find
' find A?​

Answer 1

Answer:

$given \: tan2a - cot(a - 18) \\ as \: we \: know \: \\ trigonometric \: ratio \: \\ tan \alpha = cot(90 - \alpha ) \\ so \: cot2a = cot(90 - (a - 18) \: \\ so \: 2a = 90 - a + 108 \\ so \: 3a = 198 \\ a = 63$

Answer 2

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$$\begin{lgathered}given \: tan2a - cot(a - 18) \\ as \: we \: know \: \\ trigonometric \: ratio \: \\ tan \alpha = cot(90 - \alpha ) \\ so \: cot2a = cot(90 - (a - 18) \: \\ so \: 2a = 90 - a + 108 \\ so \: 3a = 198 \\ a = 63 \\\end{lgathered}$$