Question

16 kg oxygen gas expands at STP (1 atm) isobarically to occupy double of its original volume. The work done during the process is nearby

260 kcal

180 kcal

130 kcal

271 kcal

Answer 1

Answer:

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Answer 2

Answer:

32 grams O2=1 mole

16 grams O2=0.5 mole

16×103 gram =16kg =500 moles of O2(n)

We know that,

W=−nPV, Now we know, At STP, T=273K

W=nRTInV1V2

Here n= number of moles =3216000=500R=1.986 cal

T=273K

V1V2=2

So, W=500x1.986×273×In2

            =187905 cal

            =187.905 K.cal

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