16 kg oxygen gas expands at stp isobarically to occupy double of its original volume.the work done during the process is nearly
Answers
Find number of moles in 16 kg of oxygen. Let it be n.
One mole of any gas has at STP a volume equal to 22.4 Lt = 22.4×10^−3 m^3. Let it be V.
Multiply this by number of moles obtained in the first step to find total volume of 16 kg oxygen. This will be nV.
Since volume is doubled, change in volume ΔV=nV
Use work done, W=pΔV. (p=1atm=1.013×10^5 Pa)
Your answer will be in joules. You can divide that by 4.18 to get the answer in calorie.
Answer:
271.16Kcal
Explanation:
given 16kg O2
moles of O2=16000÷32
=500
to find volume of O2= n ×22.4×10^-3
= 11200×10^-3
w= pdv
= 1.013×10^5 ×11200×10^-3u
= 11345.6×10^2
divide this value by 4.184 to get answer in calories
=2711.6×10^2
= 271.16Kcal