Math, asked by asjadsaifi07959, 1 year ago

16 (m+n)cube +16 (m+n)square​

Answers

Answered by Anonymous
6

Answer:

16( {m + 2)}^{3}  + 16 {(m + n)}^{2}  \\  \\ 16( {m}^{3}  + 8 + 3 {m}^{2} (2 )+ 3(4)m) + 16 ({m}^{2}  +  {n}^{2}  + 2mn) \\  \\ 16 {m}^{3}  + 128 + 96 {m}^{2}  +192m + 16 {m}^{2}  + 16 {n}^{2}  + 32mn  \\  \\ 16 {m}^{3}  + 112m ^{2}  +  16n ^{2}  + 32mn + 128 + 192m

Answered by Anonymous
1

Step-by-step explanation:

16 {(m + n)}^{3}  + 16 {(m + n)}^{2}  \\  \\  =  > 16( {m}^{3}  + 3 {m}^{2} n + 3m {n}^{2}  +  {n}^{3} ) + 16( {m}^{2}  + 2mn +  {n}^{2} ) \\  \\  =  > 16 {m}^{3}  + 48 {m}^{2}n + 48m {n}^{2}   + 16 {n}^{3}  + 16 {m}^{2}  + 32mn + 16 {n}^{2}

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