Question

16 m of distance covers by an object in 5 sec and next 16

m is covers in 7 sec, calculate the average speed of the object

in,

(i) m/s

(ii) km/h​

Answer 1

Answer:

2.7 m/sec , 9.72 km/hr

Explanation:

speed 1 = 16/5 m/sec = 3.2 m/sec

speed 2 = 16/7 m/sec = 2.285 m/sec = 2.3 m/sec

Avg speed =

$\frac{2 \times 3.2 \times 2.3}{3.2 + 2.3} = \frac{14.72}{5.5} = 2.676 = 2.7$

2.7 m/sec.

in km/hr , we have to multiple with 18/5

$2.7 \times \frac{18}{5} = \frac{48.6}{5} = 9.72$

9.72 km/hr