Question

16.Match:
a. 256a2 - 441b2
(9a - 7b) ( 9a - 7b)
b. 81a2 - 126 ab + 49 b2
(2a - bh c) ( 2a + b + c)
c. 4a2-02-2bc - c2
(16a - 21b ) ( 16a + 21b)​

Answer 1

Answer:

a. 256a2 - 441b2= (16a-21b)(16a+21b)

b. 81a2-126ab+49b2=(9a-7b)(9a-7b)

c. 4a2-02-2bc-c2= (2a-b+C)(2a+b+C)