Question

16 me of a hydrocarbon gas was exploded
with exces
of oxygen
On cooling, the vo the
volume of the resulting gaseous mixture was
reduced by 48 me. When KOH was added
there was a further decrease of 48 me in the
volume. Find the molewlar formula of the compound​

Answer 1

Answer:

Explanation:

X=3

Volume contraction =48

Volume of hydrocarbon +volume of oxygen reacted -volume of co2 = 48

16+v-48 = 48

V=80

X+y/4 = 5

Y=8

C3h8