16 men can complete a piece of work in 20 days. They started the work and after 5 4) 7.8 5) 16.4 days 6 men left. In how many days will the work be completed by remaining men ? 1) 28 2) 16 3) 42 4) 36 5) 24
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16/3 is the answer thanks
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Here’s your answer…
Given,
16 men complete a work in = 20 days
Formula:
Total work = Efficiency × Time
M1 × D1 = M2 × D2
Calculation:
Work done by 16 men in 20 days = 16 × 20
Work done by 16 men in 12 days = 16 × 12
Remaining work = 16 × 20 – 16 × 12 = 16 (20 – 12) = 16 × 8
If 8 more men join the team, then number of men = 16 + 8 = 24
Let 24 men complete the remaining work in x days, then
According to the question
24 × x = 16 × 8
⇒ x = (16 × 8)/24
∴ x = 16/3 days
Hope it helps<3
Pls mark as the brainliest
Given,
16 men complete a work in = 20 days
Formula:
Total work = Efficiency × Time
M1 × D1 = M2 × D2
Calculation:
Work done by 16 men in 20 days = 16 × 20
Work done by 16 men in 12 days = 16 × 12
Remaining work = 16 × 20 – 16 × 12 = 16 (20 – 12) = 16 × 8
If 8 more men join the team, then number of men = 16 + 8 = 24
Let 24 men complete the remaining work in x days, then
According to the question
24 × x = 16 × 8
⇒ x = (16 × 8)/24
∴ x = 16/3 days
Hope it helps<3
Pls mark as the brainliest
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