Question

16 ml of a hydrocarbon gas was exploded with excess of oxygen on cooling the volume of resulting gaseous mixture was reduced by 48 ml. When KOH added there was for the decrease of 48 ml in volume ,find the molecular formula​

Answer 1

Answer:

The molecular formula of hydrocarbon is $\mathbf{C}_{3} \mathbf{H}_{6}$

Explanation:

Hydrocarbon has carbon and hydrogen. The general molecular formula of hydrocarbon is $\mathrm{C}_{\mathrm{x}} \mathrm{H}_{\mathrm{y}}$

“x” denotes number of carbon atoms in hydrocarbon and “y” denotes number of hydrogen atoms in hydrocarbon.

From the given,  

Volume of hydrocarbon = 16 ml

Volume of gaseous mixture = 48 ml

Reduce volume of KOH = 48 ml

Total volume of hydrocarbon (n) = 16 ml

n=16 ml

nx=48

$x=\frac{48}{16}=3$

Therefore, number of carbon atoms are three.

ny=48 ml

y=\frac{48}{16}=3

Each water molecule has two hydrogen,$y=3 \times 2=6$

Therefore, number of hydrogen atoms are six.

Hence , the molecular formula of hydrocarbon is $\mathrm{C}_{3} \mathrm{H}_{6}$

Answer 2

Answer:

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