Question

16. Name much work is done when 1μC charge moves against a potential difference of 2 V?

Answer 1

Answer:

0.002J

Step-by-step explanation:

W=Vq

W=1/1000*2

Answer 2

QuesTion:

How much work is done when 1 μC charge moves against a potential difference of 2 V ?

SoluTion:

charge , Q = 1 μC = 1*10⁻⁶ C = 10⁻⁶ C

potential difference , V  = 2 V

work done , W =  ?

As , we know

V = W / Q

so,

W = V * Q

so,

W = 2 * 10⁻⁶ J

W = 0.000002  J .