Question

16 no kijiyega ok Sir​

Answer 1

Answer:

y = 4  (not full answer this is hints) ⬇

Step-by-step explanation:

Given,

      $\frac{6y +1}{2+1}$  = $\frac{7y-3}{3}$

=>  3 (6y + 1) = (2+1) (7y-3)           [ cross multiplication ]

=>  18y + 3 = 14y - 6 + 7y -3

=>  18y -14y -7y  = -6 -3 -3

=>  18y - 21 = -12

=>  -3y = -12             [  minus minus cancel ]

=>  3y = 12

=>  y = $\frac{12}{3}$

=>  y = 4

check the answer

put y = 4,

      $\frac{6y +1}{2+1}$ =  $\frac{7y-3}{3}$

=>  $\frac{6(4) +1}{2+1}$ = $\frac{7(4)-3}{3}$

=>  $\frac{24 +1}{2+1}$ = $\frac{28-3}{3}$

=>  $\frac{25}{3}$ =

=> L.HS = R.H.S

..Hope this solution help you