Question

16. On the basis of VSEPR theory predict the shape of Following molecule
i. SF4 ii. CIF5 iii.NO2
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Answer 1

$\sf{\underline {\Large {VSEPR\:Theory}}}$ :

$\tt{Valence \:Shell\: Electron\: Pair \:Repulsion \:Theory}$ (VSEPR).

According to this theory, we can determine the shape of the molecules by the number of electrons in Bonding and Anti - Bonding ( B. M. O. or A. B. M. O. ) in the valence shell of the central atom.

➡️ $\fbox{\tt{Hybridisation\:=\:\frac{1}{2} \:(V\:+\:M\:-\:C\:+\:A\:)}}$

V = Number of valence electrons.

M = Number of mono - valent atoms on central atom.

C = Number of charges on cation.

A = Number of charges on anion.


⚫$\sf{\large {\underline {SF_4}}}$ :

$\tt{H\:=\:\frac{1}{2} \:(6\:+\:4\:-\:0\:+\:0\:)}$

H = 5 = $\tt{sp^{3}d}$

$\sf{\underline {Shape}}$ : Refer the attached picture.

⚫$\sf{\large {\underline {ClF_5}}}$ :

$\tt{\: H \:=\:\frac{1}{2} \:(7\:+\:5\:-\:0\:+\:0\:)}$

H = 6 = $\tt{sp^{3}d^{2}}$

$\sf{\underline {Shape}}$ : Refer the attached picture.

⚫$\sf{\large {\underline {NO_2}}}$ :

$\tt{\: H \:=\:\frac{1}{2} \:(5\:+\:\:-\:0\:+\:0\:)}$

H = 2.5

$\tt{\fbox{NOTE}}$ : In $\tt{NO_2}$, O is more electronegative than N, so when central atom is more electronegative than surrounding atom, than

H = 2.5 + 0.5 = 3

H = $\tt{sp^{2}}$

$\sf{\underline {Shape}}$ : Refer the attached picture.

Answer 2

Explanation:

structure of SF4 WITH ALL STEPS