Question

(16. P is a point on the side BC of a triangle ABC such that AB= AP. Through A and C
lines are drawn parallel to BC and PA respectively, so as to interest at D as shown
in the figure. Show that ABCD is a cyclic quadrilateral
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Answer 1

Since we have a quadrilateral ABCD that is a cyclic quadrilateral, AP and DC intersect in points and lines Ab and BC intersect in. our aim is to show that the circle inscribed in the triangle ABC AB and CD intersect in point ji on line a.m..

So we need to consider the fact that our triangle has angles inside the circumference which let us know that AP and DC intersect in a point since our aim is to prove that intersection in is equal to lines AB and BC, then proved.

PLZ MARK AS BRAINLEIST

Answer 2

Answer:

1+4=180

Step-by-step explanation:

Angel 1= angel 2= 180

angel 2 +Angel 3=180