Math, asked by saurupa99, 11 months ago

√16-p=p-4 solve for p

Answers

Answered by pallaviv937

$\sqrt{16} = 4 \\ 4 - p = p - 4 \\ 4 + 4 = p + p \\ 8 = 2p \\ p = 4 \\ \\$

rosangiri28pfbc5r: wrong

Answered by chinnaribhavitp3vx29

$\sqrt{16} - p = p - 4 \\ 4 - p = p - 4 \\ 4 + 4 = p + p \\ 8 = 2p \\ p = 8 \div 2 \\ p = 4 \\$
Here is the answer

chinnaribhavitp3vx29: why

chinnaribhavitp3vx29: where

rosangiri28pfbc5r: square root of 16-p = p-4 , squaring bothsides we get, 16-p= (p-4)^2 or, 16-p= p^2-8p-4^2 or, p^2-9p=0 or, p (p-9) = 0 so p= 0 or 9 is right answer

chinnaribhavitp3vx29: let me report my answer...

chinnaribhavitp3vx29: can you report my answer...

chinnaribhavitp3vx29: I can't report it as there is no option...

saurupa99: sir, i too got 9 as the answer

saurupa99: but in the answer sheet the ans given is p=7

rosangiri28pfbc5r: p = 7 is wrong. Sometimes, answer mistakenly written in book .You have to believe on you and your teachers confidently .Don't depend only on book

saurupa99: 7 is correct sir , i just did a mistake in changing the sign while transposing

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