Question

16.
Position of a body changes with time as x = (t²- 4) m, where tis in second. The
average velocity of the body in first 2 s is

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

4m/s

Explanation:

Vavg.= d(t²-4)/dt

2t -0

2t

in 2 sec = 2t

2*2

4m/s