Question

16. Present age of father is 42 years and that of his son is 14 years. Find the ratio of

(a) Present age of father to the present age of son.

(b) Age of the father to the age of son, when son was 12 years old.

(c) Age of father after 10 years to the age of son after 10 years.

(d) Age of father to the age of son when father was 30 years old.​

Answer 1

Explanation:

(a) Ratio of father’s present age to that of son= \frac{42}{14}=\frac{3}{1}=3:1

(b) When son was 12 years, i.e., 2 years ago, then father was (42 – 2) = 40 years

Therefore, the ratio of their ages = \frac{42}{14}=\frac{3}{1}=3:1

(c) Age of father after 10 years = 42 + 10 = 52 years

Age of son after 10 years = 14 + 10 = 24 years

Therefore, ratio of their ages = \frac{42}{14}=\frac{3}{1}=3:1

(d) When father was 30 years old, i.e., 12 years ago, then son was (14 – 12) = 2 years old

Therefore, the ratio of their ages = \frac{30}{2}=\frac{15}{1}=15:1

Answer 2

Answer:

a)7:2. b) 10:3. c)13:6. d)15:1

Explaination:

a)42/14=7/2=7:2

b)when the son was 12 means 14-2=12

so the age of father is 42-2=40

so,40/12=10/3=10:3

c)Father's age after 10 years =present age +10

42+10=52

son's age after 10 years=present age +10

14+10=24

so ratio=52/24=26/12=13/6=13:6

d)father was 30 years=42-30=12

means son is 12 years younger than father so son 's age is present age -12

14-12=2

ratio =30/2=15/1=15:1