Question

16. Rationalise the denominator.
please solve this correctly.​

Answer 1

Answer:-

$\frac{1}{ (\sqrt{3} + \sqrt{2} ) - 1 } \times \frac{ (\sqrt{3} + \sqrt{2}) + 1 }{ (\sqrt{3} + \sqrt{2}) + 1}$

$= \frac{ (\sqrt{3} + \sqrt{2}) + 1}{ {( \sqrt{3} + \sqrt{2})}^{2} - {1}^{2} } = \frac{ (\sqrt{3} + \sqrt{2}) + 1}{ 3 + 2 + 2 \sqrt{6} - 1 }$

$= \frac{ (\sqrt{3} + \sqrt{2}) + 1}{ 4 + 2 \sqrt{6} }$