Question

16÷root 41 -5 rationalise.​

Answer 1

$\huge \pink{ \boxed{ \sf{ \red{Question:-}}}}$

➭16÷ root 41-5 or

$\huge \frac{16}{ \sqrt{41} - 5}$

$\pink{ \boxed{ \sf{ \green{Answer:-}}}}$

According to question:-

$= \frac{16}{ \sqrt{41} - 5 } \times \frac{ \sqrt{41} + 5 }{ \sqrt{41} + 5}$

$= \frac{16( \sqrt{41} - 5) }{ {( \sqrt{41}) }^{2} - ( {5})^{2} }$

$= \frac{16( \sqrt{41} - 5) }{41 - 25}$

$= \frac{16( \sqrt{41} - 5) }{16}$

$= \frac{ \sqrt{41} - 5 }{1}$

$\huge = \sqrt{41} - 5$

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