Question

16. Solve for y: 2x + 3y + 4z = 29
3x + y + 3z = 21
4x + 4y + 5z = 40
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Answer 1

Answer:

1.2x+3y+4z=29

=3y=29-2x-4z

=y=29-2x-4z/3

Explanation:

2..3x+y+3z=21

y=21-3x-3z

y=21-3(x-z)

3.4x+4y+5z=40

4y=40-4x-5z

y=40-4x-5z/4

hope it helps.............................................

Answer 2

y=06

Explanation:

we have to do first two equations same then we have to eliminate first two equations and then the last two