Question

16. Solve graphically: x -y=0 and 3x+2y-12=0​

Answer 1

SolutioN :

We have, Pair of Linear Equation.

$\tt \dagger \: \: \: \: \: x - y = 0.$

✎ When, x = 1.

$\tt : \implies x - y = 0.$

$\tt : \implies 1 - y = 0.$

$\tt : \implies - y = - 1.$

$\tt : \implies y = 1.$

$\rule{90}2$

✎ When, x = 2.

$\tt : \implies 2 - y = 0.$

$\tt : \implies - y = - 2.$

$\tt : \implies y = 2.$

$\rule{90}2$

✎ When, x = 3.

$\tt : \implies 3- y = 0.$

$\tt : \implies y = 3.$

$\rule{200}3$

$\tt \dagger \: \: \: \: \: 3x + 2y - 12= 0.$

$\tt : \implies 3x + 2 y - 12= 0.$

$\rule{90}2$

✎ When, x = 2.

$\tt : \implies 3(2) + 2 y - 12= 0.$

$\tt : \implies 2 y -6= 0.$

$\tt : \implies y = 3.$

$\rule{90}2$

✎ When, x = 4.

$\tt : \implies 3x + 2 y - 12= 0.$

$\tt : \implies 3(4) + 2 y - 12= 0.$

$\tt : \implies 12 + 2 y - 12= 0.$

$\tt : \implies y = 0.$

$\rule{90}2$

✎ When, x = - 2.

$\tt : \implies 3x + 2 y - 12= 0.$

$\tt : \implies 3( - 2) + 2 y - 12= 0.$

$\tt : \implies - 6 + 2 y - 12= 0.$

$\tt : \implies 2 y - 18= 0.$

$\tt : \implies y = 9$

☛ Graph provide Above ↑.

Answer 2

Step-by-step explanation:

We have, Pair of Linear Equation.

\x - y = 0.†x−y=0

✎ When, x = 1.

x - y = 0.:⟹x−y=0.

1 - y = 0.:⟹1−y=0.

- y = - 1.:⟹−y=−1.

y = 1.:⟹y=1.

✎ When, x = 2.

2 - y = 0.:⟹2−y=0.

- y = - 2.:⟹−y=−2.

y = 2.:⟹y=2.

✎ When, x = 3.

3- y = 0.:⟹3−y=0.

y = 3.:⟹y=3.

3x + 2y - 12= 0.†3x+2y−12=0.

3x + 2 y - 12= 0.:⟹3x+2y−12=0.

\

\✎ When, x = 2.

3(2) + 2 y - 12= 0.:⟹3(2)+2y−12=0.

2 y -6= 0.:⟹2y−6=0.

y = 3.:⟹y=3.

✎ When, x = 4.

3x + 2 y - 12= 0.:⟹3x+2y−12=0.

3(4) + 2 y - 12= 0.:⟹3(4)+2y−12=0.

12 + 2 y - 12= 0.:⟹12+2y−12=0.

y = 0.:⟹y=0.

✎ When, x = - 2.

3x + 2 y - 12= 0.:⟹3x+2y−12=0.

3( - 2) + 2 y - 12= 0.:⟹3(−2)+2y−12=0.

- 6 + 2 y - 12= 0.:⟹−6+2y−12=0.

2 y - 18= 0.:⟹2y−18=0.

\y = 9:⟹y=9