16)State Factor Theorem. Using this Theorem factorise x cube-3x square -x+ 3
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Factor theorem says : if P(k) = 0 for a polynomial P(x) in x, then (x-k) is a factor.
P(x) = x³ - 3 x² - x + 3
we see that for x = 1, P(x) = 0.
so P(x) = (x - 1) (x² - a x -3 )
= x³ - ( 1+ a) x² - (3-a) x +3
compare coefficients to get a = 2
x² - 2 x - 3 = (x-3)(x+1)
P(x) = (x-1) (+1)(x-3)
P(x) = x³ - 3 x² - x + 3
we see that for x = 1, P(x) = 0.
so P(x) = (x - 1) (x² - a x -3 )
= x³ - ( 1+ a) x² - (3-a) x +3
compare coefficients to get a = 2
x² - 2 x - 3 = (x-3)(x+1)
P(x) = (x-1) (+1)(x-3)
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