Math, asked by aryan821060, 8 months ago

16 Subtract the sum of (7pq - 3qr + 4rs) and (9qr + 3rs - 5pq) from the sum of (2ar - 4rs + 6pq) and (11pq - 34
+5rs).
nu
please right answer please
Answers is 15pq-7qr-6rs​

Answers

Answered by hkishor60gmailcom
0

sum of (7pq-3qr+4rs)+(9qr+3rs-5pq)

= 16pq-8qr+7rs

sum of (2ar-4rs+6pq)+(11pq-34+5rs).

= 2ar+17pq+1rs-34

Required difference:- 2ar+17pq+1rs-34 -(16pq-8qr+7rs) = 2ar+pq-6rs+8qr-34

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