Question

(16×$2^{n+1}$-4×$2^{n} }$)÷16×$2^{n+2}-2$×$2^{n+2}$

Answer 1

$\frac{16*2^{n+1}-4*2^{n}}{16*2^{n+2}-2*2^{n+2}}$
$= \frac{2^{4}*2^{n+1}-2^{2}*2^{n}}{2^{n+2}(16-2)}$
$= \frac{2^{3}*2^{1}*2^{n+1}-2^{n+2}}{2^{n+2}(16-2)}$
$= \frac{8*2^{n+2}-1*2^{n+2}}{2^{n+2}(16-2)}$
$= \frac{2^{n+2}(8-1)}{2^{n+2}(16-2)}$
$= \frac{7}{14}$
$= \frac{1}{2}$

Hope this may help you.