Question

16. The coefficient of linear expansion of iron is
0.000011 per K. An iron rod is 10 m long at 27°C. The length of the rod will be decreased by 1.1 mm when the temperature of the rod changes to :
(1) 0°C
(2) 10°C
(3) 17°C
(4) 20°C​

Answer 1

Answer:17 °C

Step-by-step explanation:

coefficient of linear expansion,k=0.000011 /°K

initial length of iron rod,L1=10 m = 10000 mm

initial temperature of rod,T1=27 °C

decrese in length of rod,ΔL=L1-L2=1.1 mm

Formula for linear expansion coefficient, $k=\frac{(L1-L2)}{L1*(T1-T2)}$

                                                       $0.000011=\frac{(1.1)}{10000*(27-T2)}$

                         final temperature of rod,T2 = 17 °C