Question

16) The diameter of a roller is 98 cm and its length is 120cm It takes 500 complete revolutions to move
once over to level the playground
Find the Total Surface Area of the roller in Cm​

Answer 1

Answer:

Radius of the roller (r) = 84/ 2 cm = 42 cm  Length of the roller (h) = 120 cm  Curved surface area of the roller = 2πrh  = 2 × 22/ 7 × 42 × 120 cm2 = 44 × 720 cm2 = 31680 cm2  ∴ area covered by the roller in 1 revolution = 31680 cm2  ∴ area covered by the roller in 500 revolutions = 31680 × 500 cm2 = 15840000 cm Hence, area of the playground = 15840000/ 100× 100 m2 = 1584 m2 Ans

Step-by-step explanation:

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Answer 2

Answer:

T.S.A = $\\52052$

Step-by-step explanation:

Radius of the roller (r)= $\frac{98}{2}$   cm = 49 cm

length of the roller (h)=120 cm

T.S.A is 2 π r(h + r)

= 2 x $\frac{22}{7}$ x 49 x (120 + 49)

T.S.A = $\\52052$

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