Question

16. The dimensions of a rectangular block measured
with an instrument having least count 0.01 cm is
4.0 mm x 10.0 mm x 10.0 mm. The maximum
percentage error in the measurement of volume of
the block is​

Answer 1

Answer:

Explanation:

Hey,

=> According to the question, The dimensions of a rectangular is 4.0 mm × 10.0 mm × 10.0 mm.

percentage error in the measurement of volume of  the block = ?​

=> Here, we can use following formula:

V = lbh

by placing log both the sides, we get

logV = log (lbh)

logV = logl + logb + logh

=> Now, by discriminating both sides, we obtain

dV/V = dl/l + db/b + dh/h

∴∆V/V = ∆l/l + ∆b/b + ∆h/h

= 0.1/4 + 0.1/10 + 0.1/10

= 0.025 + 0.01 + 0.01

= 0.045

=> Percentage error in the measurement of volume of  the block =  ∆V/V × 100 [multiply  ∆V/V with 100 to convert it into percentage]

= 0.04 × 100

= 4.5%