Question

16. "The displacement x of a particle of mass m kg moving in
one dimension, under the action of a force, is related to
the time by the equation t = 4x + 3 where x is in meters
and t in seconds. The work done by the force in the first
six second is​

Answer 1

Answer:

X=(t-3)/4

V=dx/dt=1/4

distance covered in 6 seconds =(6-3)/4=3/4

here velocity is constant so acceleration = 0

work done =FS

=mas

=0N(as acceleration is zero)