16. The distance between two stations A and B is 230 km
Two motorcyclists start simultaneously from A and B
in the opposite directions and the distance between
them after three hours is 20 km. If the speed of ons
motorcyclist is less than that of the other by 10 km
find the speed of each motorcyclist.
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Explanation:
Speed of first cyclist = X km/hr
Speed of other cyclist = (X - 10) km/hr
Distance covered by first cyclist after 3 hours = 3X km
Distance covered by other cyclist after 3 hours = 3(X - 10) km = (3X - 30) km
According to condition,
3X + 3X - 30 + 20 = 230
6X -10 = 230
6X = 230 + 10
6X = 240
X = 240/6
X = 40
Therefore, speed of first cyclist = X = 40 km/hr
& Speed of other cyclist = X - 10 = 40 - 10 = 30 km/hr
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