Math, asked by errolmascarenhas706, 4 months ago

16. The factorisation of y² – 7y + 12 is *

a. (y + 3)(y + 4)
b. (y + 3)(y – 4)
c. (y – 3)(y + 4)
d. (y – 3)(y – 4).

17. The factorisation of z² – 4z – 12 is

a. (z + 6)(z + 2)
b. (z – 6)(z – 2)
c. (z – 6)(z + 2)
d. (z + 6)(z – 2).​

Answers

Answered by pk9894945
0

Answer:

d. (y-3)(y-4).

c.  (z - 6) (z + 2)

Step-by-step explanation:

 y²-7y+12  

= y²-4y-3y+12

= (y²-4y)-(3y+12)

= y(y-4)-3(y+4)

= (y-3)(y-4).

 z² - 4z - 12

= z² - 6z + 2z - 12

= z(z - 6) + 2(z - 6)

= (z - 6) (z + 2)

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