16. The first term of a sequence is -12 and the ninth term is 0. Find the nth term of this sequence.
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Answer:
The nth term is (-27 + 3n)/2
Step-by-step explanation:
a = -12
a₉ = a + 8d = 0
8d = -a
d = -a/8
Put value of a = -12
d = -(-12)/8
= 12/8
= 3/2
The common difference is 3/2
aₙ = a + (n - 1)d
= -12 + (n - 1)(3/2)
= -12 + 3n/2 - 3/2
= (-24 - 3)/2 + 3n/2
= -27/2 + 3n/2
= (-27 + 3n)/2
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